A smile expresses two meanings. It says I’m approachable or friendly; and it also says I’m honest and open.()
BMy name is Tom Mallory. I'm English and I'm 13. I'm a student in Brookes School. I like music and sports very much. I can play twoinstruments :the violin and the piano. I can play them very well.I have two sisters. They are students, too. Our parents are from Ireland, but they live in London now. My mother is a teacher and my father is the manager of a small en-gineering company.( )26. Tom lives in________A.IrelandB.EnglandC.CanadaD.America
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-Well, Mary, how are you? -().A、I’m goodB、I’m pleasedC、I’m fineD、I’m nice
"If I hadn't practiced when I was younger," the musician says, "I _____ able to play so well now."A. wouldn't beB. won't beC. wouldn't have beenD. couldn't have been
- Will you be able to come to the meeting? _____________A、I’m afraid notB、I’m sorry notC、I’m not afraid soD、I’m sorry that “no”
Customers also find access slow, so I'm getting it () up.A、speededB、speedC、speeding
阅读以下说明及C++程序代码,将应填入(n)处的语句写在对应栏内。【说明】本程序的功能是实现任意两个大整数的乘法运算,例如:输入整数1:8934793850094505800243958034985058输入整数2:234584950989689084095803583095820923二者之积:209596817742739508050978890737675662366433464256830959194834854876 8534【C++代码】include<iostream.h>const int MAXINPUTBIT=100;const int MAXRESULTBIT=500;class LargeNumber{int i,j;int temp;int one[MAXINPUTBIT+1];int onebit; //one的位数int two[MAXINPUTBIT+1];int twobit; //two的位数int result[MAXRESULTBIT+1];public:LargeNumber();~LargeNumber();int inputone(); //出错返叫0,否则返回1int inputtwo(); //同上void multiplication(); //乘void clearresult(); //清零void showresult(); //显示};LargeNumber∷LargeNumber(){for(i=0;i<=MAXINPUTBIT;i++){one[i]=0;two[i]=0;}nebit=0;twobit=0;inputone();inputtwo();}LargeNumber∷~LargeNumber(){}int LargeNumber∷inputone(){char Number[MAXINPUTBIT+1];cout<<"Please enter one:";cin>>Number;i=0;j=MAXINPUTBIT;while(Number[i]!='\0')i++;nebit=i;for(i--;i>=0;i--,j--){if(int(Number[i])>=48&&int(Number[i])<=57)(1); //由字符转换为数字elsereturn 0;}return 1;}int LargeNumber∷inputtwo(){char Number[MAXINPUTBIT+1];cout<<"Please enter two:";cin>>Number;i=0;j=MAXINPUTBIT;while(Number[i]!='\0')i++;twobit=i;for(i--;i>=0;i--,j--){if(int(Number[i])>=48&&int(Number[i])<=57)two[j]=int(Number[i]-48); //由字符转换为数字elsereturn 0;}return 1;}void LargeNumber∷multiplication() //乘法{clearresult();int m;for(i=MAXINPUTBIT;i>=0;i--){temp=two[i];for(j=(2),m=MAXINPUTBIT;m>=0;m--,j--){result[j]+=temp*one[m];if(result[j]>9){result[j-1]+=result[j]/10;(3);}}&n
If someone says "I know the word", he should not only understand its meaning but also beable to pronounce, spell, and __________ it.A.explainB.recognizeC.memorizeD.use