A.very
B.so
C.such
D.quite
程序 include void main() { char str[][10]={ ”ok!”,“pen”,”book”,”desk”}; int i; for(i=1;iA.ok! penB.pen bookC.ok! pen bookD.ok! pen book desk
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( 10 )执行下列程序,显示的结果是 【 10 】 。one= "WORK"two = ""a = LEN ( one )i = aDO WHILE i>=1two = two + SUBSTR ( one ,i , 1 )i=i - 1ENDDO? two
下面程序的功能是:对字符串从小到大进行排序并输出,请填空。#include "string.h"#include "stdio.h"sort(char *a[],int n){ int i,j;char *p;for(j=1;j0){ p=a[i];a[i]=a[i+1];a[i+1]=p;}}main(){ int i;char *book[]={"itisme","itisyou","howareyou","fine","goodnight","goodbye"};sort( 【17】 );for(i=0;i<6;i++)printf("%s\n",book[i]);}
I()a book when the telephone().A. was reading…rangB. read…rangC. was reading…was ringing
现有:1.classBook{2.&ensp现有:1.classBook{2.privatefinalvoidread(){System.out.print("book");}3.}4.classPageextendsBook{5.publicstaticvoidmain(String[]args){6.//insertcodehere7.}8.privatefinalvoidread(){System.out.print("page");}9.}和如下三个代码片段(x,y,z):x.//justacommenty.newPage().read();z.newBook().read();分别插入到第6行,有几个允许代码通过编译并可以运行且无异常?()
执行下列程序,显示的结果是【 】。ne="WORK"two=""a=LEN(one)i=aDO WHILE i>=ltwo=two+SUBSTR(one,i, 1)i=i-1ENDDO?two
编译和执行以下代码,输出结果是( )。 int i=1; switch (i) { case 0: System.out.print("zero,"); break; case 1: System.out.print("one,"); case 2: System.out.print("two,"); default: System.out.println("default"); }A.one,B.one,two,C.one,two,defaultD.default