()father took part in the charity activity in the neighborhood yesterday?
Peter's.
A. Whose
B. What
C. Which
The Red Cross is an international (charity).()此题为判断题(对，错)。
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Max: You should go to pubs, or join a club.Peter: But... English people never speak to me.Max: Ah! You should speak to them first.Peter: (59)
TALKING ABOUT BOXING DAYA. People will give money and other giftsB. Come on. Let s go.C. Boxing Day D. Well, I see.E. Yes, indeed so. _Zhang Hua and Peter are talking about Boxing Day after dinner._ …PETER：Do you know what do we call the day after Christmas DayZHANG HUA：(1)But I don t know much about it.PETER：Boxing Day is on December 26, the day after Christmas. People celebrate theholiday in many Commonwealth nations.ZHANG HUA：(2)What would you usually do on Boxing DayPETER：(3)to charitable institutions, needy individuals, and people in service jobs. And on that day, there are many discounts in the shopping centers and department stores.ZHANG HUA：I guess the shopping centers must be very crowded.PETER：(4)Do you want to go shoppingZHANG HUA：I won t miss this opportunity.PETER：I want to go too. (5)ZHANG HUA：All right.
下列不能从“yesterday”中取出字符串“yes”的函数是()。A、MID(“yesterday”，1，3)B、LEFT(“yesterday”，3)C、MIDB(“yesterday”，1，6)D、RIGHT(MID(“yesterday”，1，3)，3)
I()up my brother from the school this afternoon.A、gotB、pickedC、took
It _____ us an hour to find out who saved the child.A、costB、spentC、paidD、took
Given the following DDL for the PARTS table:CREATE TABLE parts (part_no INT(9) NOT NULL, part_name VARCHAR(24), part_remain INT(9));All part numbers entered will be different and all rows should be displayed in order of increasing part numbers whenever the table is queried. Which of the following create index statements will meet this criteria and require the least amount of storage for the index object?（）A.CREATE UNIQUE INDEX idx_partno ON parts(part_no)B.CREATE UNIQUE INDEX idx_partno ON parts(part_name ASC)C.CREATE UNIQUE INDEX idx_partno ON parts(part_name, part_no ASC)D.CREATE UNIQUE INDEX idx_partno ON parts(part_no, part_name ASC)
