假定X和Y的价格PX和PY已知,当MRSXY>PX/PY时,消费者为达到效用最大化,他将()。A、增加购买X,减少购买YB、减少购买X,增加购买YC、同时增加购买X,YD、同时减少购买X,Y
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有如下程序:include using namespace std;class point{int x, y;public:point( int v有如下程序:#include <iostream>using namespace std;class point{ int x, y;public: point( int vx, int vy ) { X=vx; y=vy; } point() { x=0; y=0; } point operator+ ( point p1 ) { point p; int px = x + p1.x; int py = y+ p1.y; return point( px, py ); } point operator-( point p1 { point p; int px = x - p1.x; int py = y - p1.y; return point( px, py ); } void print() { cout<<x<<","<<y<<end1; }};int main(){ point p1( 10, 10 ), p2( 20, 20 ); p1 = p1 + p2; p1.print(); return ();}执行后的输出结果是( )。A.10, 10B.20, 20C.10, 20D.30, 30
有以下程序: include using namespace std; int main() {intm[5],n[5],*px,*py,k;px=m有以下程序:include <iostream>using namespace std;int main(){int m[5],n[5],*px,*py,k;px=m;py=n;for(k=1;k<4;k++){*px=k;*py=2*k;cout<<m[k-1]<<n[k-1];px++;py++;}cout<<end1;return 0;}运行后的输出结果为【 】。
有如下程序:include using namespace std;class point{intx,y;public:point( int vx,有如下程序:#include <iostream>using namespace std;class point{ int x, y;public: point( int vx, int vy ) { x = vx; y = vy; } point ( ) x = 0; y= 0; } point operator+( point p1 ) { point p; int px = x+ p1.x; int py = y + p1.y; return point( px, py ); point operator-( point p1 ) { point p; int px = x -p1.x; int py = y - p1.y; return point ( px, py ); } void print() { cout<<x<<" , "<<y<<end1; }};int main (){ point p1(10, 10 ), p2( 20, 20 ); p1 = p1 - p2; p1.print (); return 0;} 执行后的输出结果是A.10,10B.20,20C.10,20D.30,30
有如下程序: include using namespace std; class point {int x,y; public:point( i有如下程序: #include <iostream> using namespace std; class point { int x, y; public: point( int vx, int vy ) { x = vx; y = vy; } point ( ) { x = 0; y = 0; } point operator+( point pl ) { point p; int px = x + p1.x; int py = y + p1.y; return point( px, py ); } point operator-( point p1 ) { point p; int px = x - p1.x; int py = y - p1.y; return point( px, py ); } void print() { cout<<x<<", "<<y<<end1; } }; int main () { point pl ( 10, 10 ), p2 ( 20, 20 ); p1 = p1 + p2; p1.print (); return 0; } 执行后的输出结果是( )。A.10,10B.20,20C.10,20D.30,30
有如下程序:includeusing namespace std;class point{int x,y;public:point(int vx,i有如下程序: #include<iostream> using namespace std; class point { int x,y; public: point(int vx,int vy) { x=vx; y=vy; } point() { x=0; y=0; } point operator+(point p1) { point p; int px=x+p1.x; int py=y+p1.y; return point(px,py); } point operator-(point p1) { point p; int px=x-p1.x; int py=y-p1.y; return point(px,py); } void print() { cout<<x<<","<<y<<end1; } }; int main() { point p1(10,10),p2(20,20); p1=p1+p2; p1.print(); retrun 0; } 执行后的输出结果是A.10,10B.20,20C.10,20D.30,30
假设Px和Py分别表示X和Y商品的价格,当边际替代率MRSxy>Px/Py,消费者为达到最大效用,他将会()。A:增加X商品的购买,减少Y商品的购买 B:减少X商品的购买,增加Y商品的购买 C:同时增加或者减少X和Y商品的购买 D:对X和Y商品的购买数量不发生改变