172.18.128.0/21
172.18.128.0/22
172.18.130.0/22
172.18.132.0/23
假设有下面4条路由:10.23.1.0/24,10.23.2.0/24,10.23.4.0/24和10.23.7.0/24,如果进行路由汇聚,能够覆盖这4条路由的地址是(1)。网络10.75.17.0/24和10.75.28.0/24经过路由汇聚,得到的网络地址是(2)。(1)A. 10.23.0.0/24B. 10.23.0.0/23C. 10.23.0.0/22D. 10.23.0.0/21(2)A. 10.75.0.0/16B. 10.75.0.0/18C. 10.75.0.0/20D. 10.75.16.0/20
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●对下面4条路由:202.115.129.0/24、202.115.130.0/24、202.115.132.0/24和202.115.133.0/24进行路由汇聚,能覆盖这4条路由的地址是(56)。(56) A.202.115.128.0/21B.202.115.128.0/22C. 202.115.130.0/22D.202.115.132.0/23
设有下列4条路由:192.168.129.0/24、192.168.130.0/24、192.168.132.0/24和192.168.133/24,如果进行路由汇聚,能覆盖这4条路由的地址是(28)。A.192.168.128.0/21B.192.168.128.0/22C.192.168.130.0/22D.192.168.132.0/23
设有下列3条路由:172.30.129.0/24、172.30.130.0/24和172.30.132.0/24。如果进行路由汇聚,能覆盖这3条路由的地址是(29)。A.172.30.128.0/21B.172.30.128.0/22C.172.30.130.0/22D.172.30.132.0/23
设有下面4条路由:172.128.17.0/24,172.128.18.0/24,172.128.19.0/24,172.12822.0/24,如果进行路由汇聚,能覆盖这4条路由的地址是______。A.172.128.16.0/21B.172.128.17.0/21C.172.128.12.0/22D.172.128.20.0/22
设有3条路由:172.30.129.0/24、172.30.130.0/24和172.30.132.0/24。如果进行路由汇聚,能覆盖这3条路由的地址是(66)。A.172.30.128.0/21B.172.30.128.0/22C.172.30.130.0/22D.172.30.132.0/23
路由汇聚(Route Summarization)是把小的子网汇聚成大的网络,下面4个子网: 172.16.193.0/24、172.16.194.0/24、172.16.196.0/24和172.16.198.0/24,进行路由汇聚后的网络地址是(25)。A.172.16.192.0/21B.172.16.192.0/22C.172.16.200.0/22D.172.16.224.0/20