计算题:已知一有机化合物的分子式为C14H10,计算其分子量(已知C元素的分子量为12,H元素的分子量为1)
假设(AL)=85H,(CH)=29H,依次执行SUB AL,CH指令和DAS指令后,AL的值是______。A.AEHB.56HC.5CHD.14H
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假定(AL)=85H,(CH)=29H,依次执行SUB AL,CH和DAS指令后,AL的值为______。A.AEHB.56HC.5CHD.14H
class Super { public int getLenght( ) { return 4; } } public class Sub extends Super { public long getLenght( ) { return 5; } public static void main(String[] args) { Super sooper = new Super( ); Sub sub = new Sub( ); System.out.println( sooper.getLenght( ) + “,” + sub.getLenght( ) ); } } What is the output?()A、 Just after line 13.B、 Just after line 14.C、 Just after line 15.D、 Just after line 16 (that is, as the method returns).
1. class Super { 2. private int a; 3. protected Super(int a) { this.a = a; } 4. } ..... 11. class Sub extends Super { 12. public Sub(int a) { super(a); } 13. public Sub() { this.a= 5; } 14. } Which two, independently, will allow Sub to compile?()A、 Change line 2 to: public int a;B、 Change line 2 to: protected int a;C、 Change line 13 to: public Sub() { this(5); }D、 Change line 13 to: public Sub() { super(5); }E、 Change line 13 to: public Sub() { super(a); }
若累加器AX的内容为4050H,执行指令SUB AX,4040H后,AX为多少?
某化合物相对分子质量为150,下面分子式中不可能的是()A、C9H12NOB、C9H14N2C、C10H2N2D、C10H14O
把C盘路径为/SUB1的文件ASD.BAK更名为ASD,下面()命令是正确的。A、REN C://SUB1/ASD.BAK C:///SUB1/ASDB、REN C:///SUB1/ASD.BAK C://ASDC、RENAME C:///SUB1/ASD.BAKD、REN C:///SUB1/ASD.BAK ASD